excel vba match error 1004 Durand Wisconsin

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excel vba match error 1004 Durand, Wisconsin

Either way, nicely spotted. –Jean-Francois Corbett Apr 9 '15 at 8:14 @Jean-FrancoisCorbett This is where I hit my knowledge boundary - I know that without specifying, VBA will use New tech, old clothes In nomenclature, does double or triple bond have higher priority? All rights reserved. need book id, written before 1996, it's about a teleport company that sends students learning to become colonists to another world more hot questions question feed lang-vb about us tour help

You *can* change the variable by doing something like TxtSearch = CDbl(TxtSearch) Of course you must declare and dimension the variable correctly. Make space between rows constant My CEO wants permanent access to every employee's emails. Sum of neighbours How to cope with too slow Wi-Fi at hotel? when I get the error, I abort the macro and try running again, I don't see the error.

Your help is greatly appreciated. So I played around with syntax variations and it turned out that the code started to work after I removed the underscore line breaks, regardless of the worksheet being displayed. <- Physically locating the server How to handle a senior developer diva who seems unaware that his skills are obsolete? I thought that it might have something to do with the value in the TextBox being considered text while the data in Phone1 was considered a number.

How to mount a disk image from the command line? How to handle a senior developer diva who seems unaware that his skills are obsolete? CustomerSearch = Application.Match(CLng(TxtSearch),Range("Phone1"),0) or CustomerSearch = Application.Match(CDbl(TxtSearch),Range("Phone1"),0) Note that I changed the function to Application.Match. I would've tried this after typing in something like you have done.

As such, this is (slightly) harder to handle. I even tried multiplying TxtSearch.Value by 1 to convert it to a number, and it still didn't work. Share Share this post on Digg Del.icio.us Technorati Twitter Bye, Jay Reply With Quote Oct 9th, 2002,08:12 PM #3 phantom1975 MrExcel MVP Join Date Jun 2002 Location Omaha, Nebraska Posts 3,962 floppybootstomp posted Oct 14, 2016 at 3:53 PM Toe-tale Taffycat posted Oct 14, 2016 at 11:04 AM WCG Stats Friday 14 October 2016 WCG Stats posted Oct 14, 2016 at 8:00

Can Communism become a stable economic strategy? I.e. Jul 27 '15 at 21:41 add a comment| 5 Answers 5 active oldest votes up vote 1 down vote I tried several times. C) In what instances would you most likely use this?

How is the Heartbleed exploit even possible? Since Application.Match allows to be wrapped in the IsError function which traps errors that would otherwise be raised by the WorksheetFunction.Match. requiredRow = Application.WorksheetFunction.Match(CLng(myDate), Worksheets("Sheet1").Range("A1:A31"),0) A very frustrating issue with a very unhelpful error message. All contents Copyright 1998-2016 by MrExcel Consulting.

more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed As others asked, it's possibly you altered the Selection (you should not rely on this construct except for sometimes as a means of user-input, but never as a variable/object). the match does not show up. More About Us...

Your approach often works. more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed You'll be able to ask any tech support questions, or chat with the community and help others. more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed

when I get the error, I abort the macro and try running again, I don't see the error. I have tried Application.Match() and Match() alone and neither seem to work. If an upvote is what you really want as appreciation then fine, I'll just give it to you (not sure why this discussion is taking place, first time getting nitpicked on Will try to work on more screenshots in the meantime to illustrate my problem better –lyk Apr 9 '15 at 7:10 add a comment| Your Answer draft saved draft discarded

We're a friendly computing community, bustling with knowledgeable members to help solve your tech questions. It may work for you at some times and not at others, though for no good reason. Just a mystery to solve. –user1147697 Sep 27 '13 at 14:55 This code cannot create the errors you're experiencing -- specifically because it's not calling the _WorksheetFunction.Match . Xcel, Dec 3, 2007, in forum: Microsoft Excel Worksheet Functions Replies: 11 Views: 680 T.

Yes, my password is: Forgot your password? It worked ..thank you so much. Browse other questions tagged vba excel-vba match or ask your own question. Search for: Recent Posts Remove Characters in String T-SQL with No Loop Part2 Remove Characters in String T-SQL with NoLoop Store Dynamic CSS files in ASP.net Master Page usingC# Hotpoint Mistral

It seems that for various worksheet functions to work, the worksheet must be active/visible. (That's at least my latest finding after my Match() was working randomly for spurious reasons.) I hoped Determine if a coin system is Canonical Is there a place in academia for someone who compulsively solves every problem on their own? And I don't get the error all the time. Why does the material for space elevators have to be really strong?

I have tried combining the usage of .Index and .Match to do this. Sub test() Set myrange = Worksheets("Sheet1").Range("A1:CZ1") If Application.IsError((Application.Match("stockcode", myrange, 0))) Then msgbox("It worked") End Sub Is this not strange? WorksheetFunction.Match throws a 1004 error when it doesn't find an error. How do I explain that this is a terrible idea?

The time now is 05:44 AM. excel excel-vba share|improve this question edited Feb 17 '14 at 22:23 Gilgamesh 8,57731538 asked Feb 17 '14 at 21:49 user3055889 246 I've run into this issue before and Application.Match Hope this helps! I have this table, and I'm trying to find out whether the code matches it's own sub-code somewhere within the other column, however it's erroring out.

Advertisements Latest Threads Happy Birthday Captain Zed! Also when I was running it match was returning an integer. It takes just 2 minutes to sign up (and it's free!). But strange enough, what you said did work.

What kind of bicycle clamps are these? In general I add zero rather than multiply by one, but that is just a personal preference. Is there any job that can't be automated? Why would a password requirement prohibit a number in the last character?