gcc error variable-size type declared outside of any function Wardensville West Virginia

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gcc error variable-size type declared outside of any function Wardensville, West Virginia

to: int array2[3];GCC gives these errors:variable-size type declared outside of any functionvariable-sized object may not be initializedwarning: excess elements in array initializerwarning: (near initialization for `array2')Both arrays need to be global These are called Variable-sized arrays.105 Views · Answer requested by Ankur GoyalView More AnswersRelated QuestionsObjective-C (programming language): How are member functions and variables declared as public or private?Why, in C, are Format For Printing -XML -Clone This Bug -Top of page First Last Prev Next This bug is not in your last search results. int extract_value( int (&a)[10][10], int row, int col ) { return a[row][col]; } int main() { int a[10][10] = {}; a[5][5] = 1; std::cout << extract_value( a, 5, 5 ) <<

Anyhow, the problem here is that 'const' doesn't quite mean 'const' in C. For example: int array1[3]={3,2,1}; int array2[array1[0]]; //should be equiv. So as far as C is concerned, this is a variable-length array, and variable length arrays are only valid as local variables (i.e., some function's internal variable). The solution to this is defining some class that takes dynamic memory in a buffer (linear) and has a conversion from the N-coordinate system into the 1-dimensional array to obtain values,

Alex Nov 15 '05 #2 P: n/a Emmanuel Delahaye Bi*************@gmail.com wrote on 01/09/05 : Hi, The following code: #include // const int const_asize = 10; #define define_asize = 10; int Will jump onto it in the coming week. On 10 May 2004 05:30:38 -0700, fl******@easy.com (flipflop) wrote:Guys - thanks for your replies. uart, Sep 23, 2011 Sep 23, 2011 #6 phinds Insights Author Gold Member actually, "quirk" may not be quite right in this case as I think it's a specific design decision

You can't use a pointer for multidimensional arrays because of the way they are laid out in C/C++. Even if you can clearly read in the signature the dimensions of the array, those dimensions are ignored by the compiler. If you post code to this newsgroup, *please* cut-and-paste the actual code that you fed to the compiler; don't try to re-type it. Why was the identity of the Half-Blood Prince important to the story?

Martin Dickopp, Dresden, Germany ,= ,-_-. =. / ,- ) http://www.zero-based.org/ ((_/)o o(\_)) \ `-' `-'(. .)`-' `-. This is probably the problem you're encountering. The answer is: it cannot be done directly. Myers 2009-04-01 14:41:32 UTC Subject: Bug 39605 Author: jsm28 Date: Wed Apr 1 14:41:06 2009 New Revision: 145405 URL: http://gcc.gnu.org/viewcvs?root=gcc&view=rev&rev=145405 Log: PR c/39605 * c-decl.c (grokdeclarator): Pedwarn for file-scope array declarator

Oh, I think I have an idea what you might mean, but it could only be a worry in certain cases. That behavior is compatible with C. These were all easily fixed but the one with the const just bothered me a bit as to why it had that behavior. Guys - thanks for your replies.

You've got to have an array of pointers for this purpose. –Michael Krelin - hacker Sep 16 '09 at 20:43 That's correct, edited my post... –Vargas Sep 16 '09 Comment 2 Joseph S. Computer beats human champ in ancient Chinese game •Simplifying solar cells with a new mix of materials •Imaged 'jets' reveal cerium's post-shock inner strength Sep 23, 2011 #2 phinds Insights Author Also, are you compiling to the C99 standard, or the older one?

I don't think that's what the OP wanted (see underlined text). `array2' shouldn't have 3 elements because `array1' has three elements, but because the zeroth element of `array1' is 3. It didn't really think it was the latter, but I'm confused about why the code with the "const int ..." statement doesn't compile in standard C (it does however compile in You're much better off using single-dimensional arrays (or, better yet, standard containers) and writing an indexing function: inline int index (int x, int y) { return x + y * width; C++1 void fcn(int arr[100]); Тут размерность массива сразу указана, а тут C++1 void vvod(int N,int A[N],int I); Задается переменная, и эта переменная сразу выступает в кач-ве размерности массива.

One possibility is to define a macro which expands to `3', and use it to both initialize the zeroth element of `array1' and define the size of `array2'. You (and everyone else so far) omitted the third alternative: (1) static const int var = 5; (2) #define var 5 (3) enum { var = 5 }; Ignoring issues about One possibility is to definea macro which expands to `3', and use it to both initialize the zerothelement of `array1' and define the size of `array2'.Martin -- Leor Zolman --- BD The keyword "const" doesn't create a constant.

Stay logged in Physics Forums - The Fusion of Science and Community Forums > Other Sciences > Programming and Computer Science > Menu Forums Featured Threads Recent Posts Unanswered Threads Videos intialise array size using global variable Referencing a global array outside a function constant array size during declaration ?? For example:int array[3]={3,2,1};int x=array[0];main() { ... " Actually, the issues don't change much depending on /what/ you want to use that value for...the bottom line, as you've acknowledged below, is that int main(void) { int myList[ListSize]; ...

Thanks, Bahadir Nov 15 '05 #1 Post Reply Share this Question 4 Replies P: n/a Alexei A. Andrew->, Это чтобы не заниматься ерундой и объявить константу N для задания размерности надо просто int N; ? @Darky Быдлокодер 507 / 294 / 45 Регистрация: 22.11.2009 Сообщений: 892 Завершенные It should really be called something like "readonly". Related 4437JavaScript function declaration syntax: var fn = function() {} vs function fn() {}1How do I declare variables for multiple functions20Avoiding declaring private functions in class header files (C++)0Was not declared

BTW. Also it compiles OK with earlier gcc's such as kgcc. this is on gcc compiling with the following: gcc -o consttest main.c adding a -std=c99 does not make any difference. Not the answer you're looking for?

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