fast_scan.inl357 error unaligned memory accesses not supported Highland Springs Virginia

Tech Monkee's can diagnose and repair just about any problem you and your computer may come across. If your computer is running slow or you have lost your internet connection you can feel confident that we have the tools to get you back, up and running fast. 

Need onsite service? No Problem. We can come to you with one of our speedy PC response.    

Address Glen Allen, VA 23059
Phone (804) 396-4112
Website Link

fast_scan.inl357 error unaligned memory accesses not supported Highland Springs, Virginia

Then I dropped 10 best and 10 worse results and calculated an average. Is the mass of an individual star almost constant throughout its life? Read on. […] Reply to this comment Leave a Reply Click here to cancel reply. This number called indent.

Second test was ok in terms of memory alignment. Reply to this comment Alexander Sandler says: February 5, 2012 at 11:16 pm @Steve My pleasure. Not a big deal, just thought I would point that out so no one gets confused Thanks! Therefore, to avoid reading from already cached 64 bytes, we have to read once every 128 bytes.

Secondly, on multi-core systems, timestamps may vary between individual cores and therefore it doesn't make sense to do any comparison or arithmetic with timestamps provided by two different cores. AFAIK, RDTS timestamp counter increments at constant rate. EvenSt-ring C ode - g ol!f What kind of bicycle clamps are these? The theoryBACK TO TOC What could be the problem you may ask?

Your cache administrator is webmaster. To be on the safe side, try to keep your data structures memory aligned, always. When reading the memory, we have to make sure that it is not yet in the cache. It is also important for data structures that being rarely (relatively) used.

Why does argv include the program name? Then we have to repeat the test several times, drop several fastest and slowest results and calculate an average. we skip 128 bytes every iteration. What does かぎのあるヱ mean?

How do computers remember where they store things? Please come again Reply to this comment Rajath says: January 11, 2012 at 7:03 am Thanks for sharing! Older CPUs (Pentium 3 for instance and even some Pentium 4's and Xeon's) has the internal time-stamp register work in slightly different manner, incrementing every instruction and not every clock tick. The system returned: (22) Invalid argument The remote host or network may be down.

Please try the request again. Then the function does the actual test. Your cache administrator is webmaster. The resultsBACK TO TOC I did the test twice, first time with indent equals 62 and second time with indent 64, i.e.

Meet the hardwareBACK TO TOC There is one hardware limitation when dealing with rdtsc instruction. We recommend upgrading to the latest Safari, Google Chrome, or Firefox. Please visit again. clock_gettime(CLOCK_MONOTONIC) is more reliable, but has more overhead (it's a systemcall), but is by far the best way to do this." First of all, thanks for the links.

This kind of error was encountered before but resolved by itself (I did nothing). This way reading 8 bytes from offset 5 or from offset 0 makes no difference - CPU reads 64 bytes in any case. This is what I have at hand. Reply to this comment Alexander Sandler says: May 16, 2010 at 11:31 am @pradeep Thanks.

Please try the request again. I have bookmarked your site as my quick-info-handbook to start learning on! I've seen some reports about effects of aligned memory access, yet I couldn't find some numbers that give a handy indication. I ran each test 100 times, with 10 seconds delay in between.

Even when you read just one byte from the memory, CPU reads a complete cache line and places it into the cache. cuda share|improve this question edited Sep 10 '10 at 6:09 Jonathan Leffler 439k62511823 asked Sep 10 '10 at 5:42 superscalar 2302514 Problems don't resolve themselves; you changed something, and rdtscll( before ); for (i = 0; i < (area_size / step) - 1; i++) { temp = *((unsigned long *)page); page += step; } rdtscll( after ); return after - started from offset 62 and 64.

My CEO wants permanent access to every employee's emails. Also, on some older chips TSC seems to change with the power state of the CPU making it potentially very unreliable. Practice Since you have not shown the declarations for your code, we can't be sure what causes the trouble (though you do say j and high are int variables; no comment Already have an account?

What does かぎのあるヱ mean? You can read about it here:, Chapter 18, section 11. Sorry mk68000 and PowerPC. Join them; it only takes a minute: Sign up Why do I have an “unaligned memory accesses not supported” error?

share|improve this answer answered May 19 '14 at 8:53 Bartosz Karpiński 7519 add a comment| up vote 1 down vote I was able to solve this problem by changing arch value Since we're on 64-bit machine, we want to run through the complete buffer and read 8 bytes at a time. I want to measure latency on a single-consumer/multi-producer multithread queue. Actually, this article was inspired by Ulrich's writing Reply to this comment Alexander Sandler says: May 28, 2009 at 1:16 pm Originally Posted By RaineI'm curious how can we use rdtscll

C:\Program Files (x86)\MSBuild\Microsoft.Cpp\v4.0\V110\BuildCustomizations\CUDA 6.0.targets 597 9 blur I have searched for answers even on second site of and I haven't fund solution that would work for me. Can you? Such data structures tend to disappear from the cache, and has to be returned into cache, each time you access them. Secondly, on multi-core systems, timestamps may vary between individual cores and therefore it doesn't make sense to do any comparison or arithmetic with timestamps provided by two different cores.

The rdtsc instruction itself may take more time than the actual read. And thanks again for your attention. Reply to this comment Data alignment for speed: myth or reality?