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The syntax for names of array classes is described by Class.getName(). When to use "bon appetit"? By default, the package attribute of the Class argument is used, if any. Since: JDK1.0 See Also:ThreadDeath, Serialized FormSee The Java™ Language Specification: 11.2 Compile-Time Checking of Exceptions Constructor Summary Constructors Modifier Constructor and Description Error() Constructs a new error with null

Serious pitfalls in the way. How exactly does mining software work? Not the answer you're looking for? If Dumbledore is the most powerful wizard (allegedly), why would he work at a glorified boarding school?

Try this:

namespace Engine;
function
parse_classname ($name)
{
return array(
'namespace' => array_slice(explode[] c = Character.class.getDeclaredClasses(); Character contains two public member classes Character.Subset and Character.UnicodeBlock and one private class Character.CharacterCache. https://docs.kentico.com/display/K81/Publishing+web+application+projects+from+Visual+Studio 1 votesVote for this answer Mark as a Correct answer Please, sign in to be able to submit a new answer. more hot questions question feed lang-java about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology Life / Arts Culture / Recreation

more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed It's not great, but it's working. Returns FALSE if object is not an object.

Give us your feedback. API 17 is sufficient for my project so I can leave it this way. I have verified that the CMSApp_OldAppCode project was compiled and referenced by CMSApp and that LicenseNewControlExtender exists in CMSAppAppCode.dll. An example is this: public String getName() { return getClass().getSimpleName(); } However, IntelliJ reports this: Ambiguous method call.

This will navigate to a path such as $ANDROID_HOME/sources/android-20/java/lang/Object.java. Class c = Thread.State.class().getEnclosingClass(); The enclosing class of the enum Thread.State is Thread. share|improve this answer answered Nov 6 '13 at 9:24 Uwe Post 16816 add a comment| up vote 1 down vote I found a fix for this, at least on my end. java android intellij-idea share|improve this question edited Sep 19 '13 at 12:10 JJD 16.9k23112182 asked Apr 30 '12 at 15:28 Matsemann 7,200114274 12 looks like a bug in IntelliJ –MRalwasser

Object.getClass() If an instance of an object is available, then the simplest way to get its Class is to invoke Object.getClass(). Return Values Returns the name of the class of which object is an instance. So wanted to add my own way.

function get_class_name($classname)
{
if (
$pos = strrpos($classname,

reading through the definition of `\cfrac` in AMSMath In the United States is racial, ethnic, or national preference an acceptable hiring practice for departments or companies in some situations? and why the code still running? share|improve this answer edited Jul 3 '14 at 2:11 answered Mar 25 '14 at 21:42 James Wald 9,57543443 James Wald, nice answer,+1 –Ritesh Gune May 14 '14 at 4:47 Thank you so much.

c() is a benchmarking function that runs each closure run 10,000 times.)

c(
function(
$class = 'a\b\C') {
It's definitely an IntelliJ bug, but it seems to be caused by a conflict between the classes in the sourcepath and in the classpath for the Android SDK. but unfortunately, it doesn't resolve the issue. There will usually be a package attribute if Class comes from class(x) for some object.

It will probably be included in v0.9.3 –pfmaggi Nov 6 '14 at 14:37 add a comment| up vote 1 down vote Just use fragment.class.getSimpleName(); share|improve this answer answered Aug 10 '14 Can some one explain me what is it about? Therefore, most calls to getClassDef will find the class in the cache or fail to find it at all, unless inherits is FALSE, in which case only the environment(s) defined by Class.getEnclosingClass() Returns the immediately enclosing class of the class.

At the moment, though, I can't see how it could happen when the getInstance() is protected, i.e. Ideally, yes. A nice trick is to use use the current thread to get a ClassLoader when in a static context. regarding the missing asax & ashx files on publish.

The .class syntax returns the Class corresponding to the type boolean. Google has developed it in cooperation with JetBrains. Class.getDeclaredClasses() Returns all of the classes interfaces, and enums that are explicitly declared in this class. You may be prompted to do this automatically if you try to edit the file.

I used to define a dependency for Android 4.1.1.4 in the pom.xml linking to Maven Central. com.google.android android 4.1.1.4 provided Meanwhile, I provide the needed dependencies using maven-android-sdk-deployer. Copyright © 1993, 2016, Oracle and/or its affiliates. Simply remove getClass(): public String toString() { return getName(); } The previous error (wrt "static") was using Card.getName() - don't prefix a type to invoke an instance method.