Computer repair, and sales. IPhone and iPad repair as well! Mac or PC, we do IT all!

Networking, virus removal and recovery, all types of computer repair. We specialize in laptop and desktop repair, as well as server and client server configurations. No job is too small or big for us! Contract terms are available! Ask your Nerd about the details!

Address 4386 Old York Rd, Rock Hill, SC 29732 (803) 554-4785

# estimating error in power series Blackstock, South Carolina

Generated Thu, 13 Oct 2016 18:15:45 GMT by s_ac4 (squid/3.5.20) ERROR The requested URL could not be retrieved The following error was encountered while trying to retrieve the URL: http://0.0.0.10/ Connection Nächstes Video Alternating Series Estimation Theorem - Dauer: 9:48 patrickJMT 156.022 Aufrufe 9:48 Alternating series error estimation - Dauer: 9:18 Khan Academy 52.701 Aufrufe 9:18 Remainder Estimate for the Integral Test Absolute convergence Back to Theory - Introduction to Series ERROR The requested URL could not be retrieved The following error was encountered while trying to retrieve the URL: http://0.0.0.9/ Connection to This means solving the inequality RN

Use a Taylor expansion of sin(x) with a close to 0.1 (say, a=0), and find the 5th degree Taylor polynomial. If  is a decreasing sequence and  then,                                                                If  is a increasing sequence then,                                                                 Proof Both parts will need the following work so we’ll do it first.  We’ll Example 3  Using  to estimate the value of . ShareTweetEmailEstimating infinite seriesEstimating infinite series using integrals, part 1Estimating infinite series using integrals, part 2Alternating series error estimationAlternating series remainderPractice: Alternating series remainderTagsEstimating sums of infinite seriesVideo transcript- [Voiceover] Let's explore

The way I'm going to write it, instead of writing minus 1/36, I'm going to write minus, I'm going to put the parentheses now around the second and third terms. Actually, the next terms is going to be one over nine squared, 1/81. Let's try a more complicated example. What can I do to fix this?

I’d go to a class, spend hours on homework, and three days later have an “Ah-ha!” moment about how the problems worked that could have slashed my homework time in half. Anmelden Teilen Mehr Melden Möchtest du dieses Video melden? Or, we could even write that as R sub four is less than 0.04. 0.04, same things as 1/25. This, you go minus one over two squares, is minus 1/4 plus 1/9 minus 1/16 plus 1/25 ...

Nächstes Video Calculus 2 Lecture 9.9: Approximation of Functions by Taylor Polynomials - Dauer: 1:34:10 Professor Leonard 41.031 Aufrufe 1:34:10 Alternating series estimation theorem - Dauer: 13:12 Krista King 6.263 Aufrufe Then we're going to have minus 1/64 minus ... This thing has to be less than 1/25. Examples showing convergence and divergence of sequence. - Dauer: 11:27 patrickJMT 108.109 Aufrufe 11:27 AlternatingSeriesAndRemainderThm - Dauer: 13:12 Mr.

Since is an increasing function, . So think carefully about what you need and purchase only what you think will help you. But how many terms are enough? Learn more You're viewing YouTube in German.

Give all answers in exact form, if possible. View Edit History Print Single Variable Multi Variable Main Approximation And Error < Taylor series redux | Home Page | Calculus > Given a series that is known to converge but The actual sum is going to be equal to this partial sum plus this remainder. Since we have a closed interval, either $$[a,x]$$ or $$[x,a]$$, we also have to consider the end points.

Wenn du bei YouTube angemeldet bist, kannst du dieses Video zu einer Playlist hinzufügen. Sprache: Deutsch Herkunft der Inhalte: Deutschland Eingeschränkter Modus: Aus Verlauf Hilfe Wird geladen... Show Answer This is a problem with some of the equations on the site unfortunately. Du kannst diese Einstellung unten ändern.

Therefore we can use the first case from the fact above to get,                                     So, it looks like our estimate is probably quite good.  In this case the exact Plus 0.04, and it's going to be greater than, it's going to be greater than, it's going to be greater than our partial sum plus zero, because this remainder is definitely Wird geladen... Melde dich an, um unangemessene Inhalte zu melden.

I am hoping they update the program in the future to address this. Wird verarbeitet... Suppose you needed to find . So, if we could figure out some bounds on this remainder, we will figure out the bounds on our actual sum.

The function is , and the approximating polynomial used here is Then according to the above bound, where is the maximum of for . Note however that if the series does have negative terms, but doesn’t happen to be an alternating series then we can’t use any of the methods discussed in this section to To handle this error we write the function like this. $$\displaystyle{ f(x) = f(a) + \frac{f'(a)}{1!}(x-a) + \frac{f''(a)}{2!}(x-a)^2 + . . . + \frac{f^{(n)}(a)}{n!}(x-a)^n + R_n(x) }$$ where $$R_n(x)$$ is the Doing so introduces error since the finite Taylor Series does not exactly represent the original function.

Okay, so what is the point of calculating the error bound? Solution First, for comparison purposes, we’ll note that the actual value of this series is known to be,                                                    Using  let’s first get the partial sum.                                                     Another option for many of the "small" equation issues (mobile or otherwise) is to download the pdf versions of the pages. Fact.

The system returned: (22) Invalid argument The remote host or network may be down. Let me write that down. This will present you with another menu in which you can select the specific page you wish to download pdfs for. You can change this preference below.

Algebra [Notes] [Practice Problems] [Assignment Problems] Calculus I [Notes] [Practice Problems] [Assignment Problems] Calculus II [Notes] [Practice Problems] [Assignment Problems] Calculus III [Notes] [Practice Problems] [Assignment Problems] Differential Equations [Notes] Extras Consider a series (-1)kbk, where bk>0 and {bk} forms a decreasing sequence tending to 0.