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Get ahead by writing an explicit (cast) in your code. –Hans Passant Oct 6 '13 at 22:24 2 Suppressing errors won't make the errors go away. For instance, when a function is inlined, a warning may mean that the line is unreachable in only one inlined copy of the function. if (flagA) foo (0); #if SOME_CONDITION_THAT_DOES_NOT_HOLD if (flagB) #endif foo (1); The warning is not issued after a #line directive, since this typically indicates autogenerated code, and no assumptions can be For example: switch ((int) (a == 4)) { ... } This warning is enabled by default for C and C++ programs. -Wswitch-unreachableWarn whenever a switch statement contains statements between the controlling

A feature to report any failure to conform to ISO C might be useful in some instances, but would require considerable additional work and would be quite different from -pedantic. For example you would need to do void* buffer = operator new(100); unsigned char* etherhead = static_cast(buffer); ^ cast If you want a dynamically allocated buffer of 100 unsigned char Note this option can only be used with the -Wuninitialized option, which in turn only works with -O1 and above. There is no "warning" for this kind of invalid conversion that you can switch off and on with -Werror because it's not a real warning - it's an error that -fpermissive

However, the standards committee have ruled that function calls do not overlap. This is a common cause of error, as programmers often forget that this type is signed on some machines. When the exact number of bytes written by a format directive cannot be determined at compile-time it is estimated based on heuristics that depend on the level argument and on optimization. For instance, the following comparison is always false: int n = 5; ...

This option is enabled by -Wall. Note these are only possible candidates, not absolute ones. They do not occur for variables or elements declared volatile. up vote 55 down vote favorite 15 I'd like to know what switch you pass to the gcc compiler to turn off unused variable warnings?

The attributes currently supported are listed below. -Wsuggest-attribute=pure-Wsuggest-attribute=const-Wsuggest-attribute=noreturn Warn about functions that might be candidates for attributes pure, const or noreturn. This includes standard functions, and others specified by format attributes (see Function Attributes), in the printf, scanf, strftime and strfmon (an X/Open extension, not in the C standard) families. This warning is enabled by -Wall. -Wunused-parameterWarn whenever a function parameter is unused aside from its declaration. This option also warns when a non-volatile automatic variable might be changed by a call to longjmp.

See Function Attributes. -Wunknown-pragmasWarn when a #pragma directive is encountered which is not understood by GCC. This construct, known from C++, was introduced with ISO C99 and is by default allowed in GCC. An alternative to increasing the size of the destination buffer is to constrain the range of formatted values. contains a const-violation.

Last edited on Dec 30, 2013 at 7:27am UTC Dec 30, 2013 at 7:39am UTC JLBorges (8473) > I think there is something wrong with my environment because I get a bar(100) ; is the instantiation of the template without #pragma GCC diagnostic ignored "-Wunused-parameter" ; it is the one that generates a diagnostic. A function-like macro that appears without arguments. This kind of attitude is not going to get you far on SO... –R..

For C++, a function without return type always produces a diagnostic message, even when -Wno-return-type is specified. These include all ISO C90 and C99 features, as well as features from the Single Unix Specification and some BSD and GNU extensions. share|improve this answer answered May 17 '12 at 6:59 user529758 add a comment| up vote 1 down vote Looks like you want to add a prefix of x to the hex Another common use of unreachable code is to provide behavior which is selectable at compile-time. -WinlineWarn if a function can not be inlined and it was declared as inline.

In order to get a warning about an unused function parameter, you must either specify -Wextra -Wunused (note that -Wall implies -Wunused), or separately specify -Wunused-parameter. -WuninitializedWarn if an automatic variable The precision of the warnings depends on the optimization options used. -Winit-self (C, C++, Objective-C and Objective-C++ only)Warn about uninitialized variables that are initialized with themselves. Show that a nonabelian group must have at least five distinct elements Animal Shelter in Java Export The $PATH Variable, Line-By-Line How exactly does the typical shell "fork bomb" calls itself In C99 mode (-std=c99 or -std=gnu99), this warning is enabled by default and it is made into an error by -pedantic-errors.

Any of several floating-point events that often indicate errors, such as overflow, underflow, loss of precision, etc. (C++ only) An enumerator and a non-enumerator both appear in a conditional expression. (C++ This allows the use of new -Wno- options with old compilers, but if something goes wrong, the compiler warns that an unrecognized option is present. -Wpedantic-pedanticIssue all the warnings demanded by Typically, the compiler warns if a const char * variable is passed to a function that takes a char * parameter. In C++, warn if a non-static reference or non-static const member appears in a class without constructors.

See Options Controlling C Dialect. Bar to add a line break simply add two spaces to where you would like the new line to be. Other than as expressed by the sequence point rules, the order of evaluation of subexpressions of an expression is not specified. However, that is a very useful warning indeed if you care about these things in your project.

If you are deliberately trying to compile non-conforming code, then using -Werror makes no sense, because you know your code contains errors and will therefore result in warnings, even with -fpermissive, A function declared external in one block and then used after the end of the block. Note this option can only be used with the -Wuninitialized option. Typically, the compiler warns if a const int (*)[] variable is passed to a function that takes a int (*)[] parameter.

The specifier for a warning is appended; for example -Werror=switch turns the warnings controlled by -Wswitch into errors. Again, these are only possible candidates. void func(unsigned number, const int). It is unaffected by backslashes in the string. –Dietrich Epp May 17 '12 at 7:13 | show 5 more comments up vote 1 down vote Escape the \ with another \

It warns about code that might break the strict aliasing rules that the compiler is using for optimization. Here is one example of how this can happen: { int x; switch (y) { case 1: x = 1; break; case 2: x = 4; break; case 3: x =