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gcc parse error at end of input Voorheesville, New York

Functions declared void do not need return statements. Ideas? It lists the line as the very last line of my .c file "}"My code compiled fine yesterday, and I only made some minor adjustments today. All rights reserved.

share|improve this answer answered Mar 25 '11 at 3:38 zwol 68.6k20116199 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign But that's ok. I did that and by the way thanx for that because knowing that may save e a lot of problems in the future. Then if you get an error message stating that it cant find libcomedi, you'll need to pass a -L flag to let the linker know in what directory it can find

When using gcc the main function of a C program must return a value of type int (the exit status of the program). asked 5 years ago viewed 2451 times active 5 years ago Related 0Compile error with inner class (bracket expected)1Parsing input with strtok in C0Parse data from input string0Parsing user input in Getting started with C or C++ | C Tutorial | C++ Tutorial | C and C++ FAQ | Get a compiler | Fixes for common problems Thread: Parse error at end This error message indicates that the compiler has encountered a variable name which does not have a corresponding declaration.

Note that non-constant initializers are allowed in C++. <<< previous table of contents next >>> Published under the terms of the GNU General Public License Design by For example, the following code: #include /* To shorten example, not using argp */ int main() { if (1==1) { printf ("Hello, world!\n"); return 0; } generates the following error: if (islower(testo[i])) testo[i] = toupper(testo[i]); else if (isupper(testo[i])) testo[i] = tolower(testo[i]); } printf("testo convertito: %s\n", testo); return 0; } lampshade View Public Profile View Extended RPG Stats Challenge This User To It can be caused by a missing declaration, or a typing error in the name.

Add This Thread To: Del.icio.us Digg Google Spurl Blink Furl Simpy Y! These warnings occur when a pointer is used incorrectly, violating a type qualifier such as const. John Nov 14 '05 #3 P: n/a Ben Pfaff "John Hanley" writes: I just received a "parse error at end of input" when compiling my code, but am unsure why. Join Date Dec 2001 Posts 680 Is it because you forgot the } at the end of else ??? 06-05-2002 #3 erikcn View Profile View Forum Posts Visit Homepage Registered User

i + 4; 2 + 4; 1 + 9; I think what you want is the compound operators: _op3 <<= 7; This is equivalent to: _op3 = op3 << 7; share|improve Variable names are case-sensitive, so foo and Foo represent different variables. Quick Navigation C++ Programming Top Site Areas Settings Private Messages Subscriptions Who's Online Search Forums Forums Home Forums General Programming Boards C++ Programming C Programming C# Programming Game Programming Networking/Device Communication Example: int main (void) { char c = "\n"; /* incorrect */ return 0; } The variable c has type char, while the string "\n" evaluates to a const char *

cov(x,y)=0 but corr(x,y)=1 more hot questions question feed lang-c about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology Life / Arts current community chat Stack Overflow Meta Stack Overflow your communities Sign up or log in to customize your list. Powered by vBulletin Version 4.2.3 Copyright © 2016 vBulletin Solutions, Inc. sumthing? 06-02-2002 #2 Traveller View Profile View Forum Posts Registered User Join Date May 2002 Posts 317 This is what I noticed right off: Code: char word[502]; int decimal[502]; void binary();

You probably have some form of unbalanced parentheses or quoting, though the compiler should give you a more usable error message. Example: struct btree * data; int main (void) { data->size = 0; /* incomplete type */ return 0; } This program has a forward declaration of the btree struct data. I am using the DJGPP compiler. In particular, the stream stdout is not required to be a constant by the C standard (although on some systems it is a constant).

It is often caused by a missing closing brace somewhere. If that function is in a >> library, you probably just need to modify the -L flag so the linker >> can find it. >> >> >> >> Jordi Vendrell wrote: Ideas? All rights reserved.

Similar topics How to Parse a File in C SAX XML Parse Python error message parse error or infinite loop? It can be caused by failing to include a header file, or otherwise forgetting to provide a function prototype. The time now is 08:16 PM. I still got that same error though?

All rights reserved. Often a missing curly bracket will cause one of these errors. character constant too long In C and C++ character codes are written using single quotes, e.g. 'a' gives the ASCII code for the letter a (67), and '\n' gives the ASCII Follow-Ups: Re: parse error at end of input From: Satish Banukumar Error manual for SystemC From: Satish Banukumar sc_pvector From: Satish Banukumar References: parse error at end of input From: Satish

There's a bug in your source, clearly, but I would argue that such a poor diagnostic is a bug in the compiler. In C and C++ it is possible to declare pointers to structs before declaring their struct layout, provided the pointers are not dereferenced--this is known as forward declaration. HTH, --Eljay Follow-Ups: Re: parse error at end of input :( From: Jordi Vendrell References: parse error at end of input :( From: Jordi Vendrell Re: parse error at end of This warning is suppressed if the assignment is enclosed in additional parentheses to indicate that it is being used legitimately.

At least I found the problem. Get Started with C or C++ C Tutorial C++ Tutorial Get the C++ Book All Tutorials Advanced Search Forum General Programming Boards C++ Programming Parse error at end of input?? more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed Lol, thank you! –Megan Rose Mar 25 '11 at 3:39 add a comment| 4 Answers 4 active oldest votes up vote 2 down vote accepted you are using //AND } for