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gcc compiler error crosses initialization Waccabuc, New York

For example, a project's policy might require that all sources compile with -Werror but certain files might have exceptions allowing specific types of warnings. A program that jumps from a point where a local variable with automatic storage duration is not in scope to a point where it is in scope is ill-formed unless the switch (val) { case VAL: { // This will work int newVal = 42; break; } case ANOTHER_VAL: ... Browse other questions tagged c++ g++ initialization switch-statement or ask your own question.

Conference presenting: stick to paper material? I think that C compiler does not even allow declaration to come after some code. My guess is that the limitation is because of this kind of confusion. To get around it, do this: switch (val) { case VAL: { // This **will** work int newVal = 42; } break; case ANOTHER_VAL: ...

share|improve this answer answered Oct 20 '12 at 20:15 stark 5,75611027 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign What happens if one brings more than 10,000 USD with them in the US? True or False? Because the error messages complains about (among other things) initialization of 'MessageEvent* me', and there is no me variable anywhere in the posted code? –Joachim Pileborg Jul 20 '12 at 12:31

Thanks CornedBee. Why doesn't ${@:-1} return the last element of [email protected]? Just spotted why it doesn't warn: it doesn't warn because the variable is just defined but not initialized. Compiler does not have to perform "local allocation" in either case (and in practice it won't). –avakar Mar 6 '10 at 15:16 add a comment| Your Answer draft saved draft

This is semantically equivalent: goto label; int x; label: cout << x << endl; However that wouldn't be possible, if x was initialized at point of declaration: goto label; int x share|improve this answer answered Jan 1 '15 at 18:17 Dalmas 19.1k64565 add a comment| up vote -1 down vote I believe the issue at hand is that is the statement was It would be cheaper to just get a computer which is 25% faster. 11-18-2006 #5 CornedBee View Profile View Forum Posts Visit Homepage Cat without Hat Join Date Apr 2003 Posts asked 3 years ago viewed 4089 times active 3 years ago Related 3g++ compiler error with templated base class member0What do these line numbers mean in this error?0Enable unreferenced local variable

Search Engine Optimisation provided by DragonByte SEO v2.0.32 (Pro) - vBulletin Mods & Addons Copyright © 2016 DragonByte Technologies Ltd. share|improve this answer answered Sep 18 '08 at 13:22 slim 16.3k44481 -1 here int x wil be never executed. Just to clarify this strictly has nothing to do with the declaration. I'm curious to know why creating an anonymous object appears to be an exemption. –Olumide May 31 at 14:03 not a DV, but: The whole question is about declaring/scope

Unproven vs. goto lx; // ill-formed: jump into scope of a // ... ly: X a = 1; // ... In C++, the problem here is one of scope.

And, I got about the same error message: example1.cc:8:7: warning: unused variable 'i' [-Wunused-variable] int i = 0; ^ example1.cc:6:3: error: goto into protected scope goto end; ^ example1.cc:8:7: note: jump Browse other questions tagged c++ or ask your own question. Initialisation is the problem. Jumps that bypass initialization are illegal in C++.

The problem is that it is possible for r to come to scope without its initializer being executed. gcc error message is : cross initialization of 'int i' –zhaorufei Dec 26 '11 at 9:50 add a comment| up vote 3 down vote Interesting that this is fine: switch (i) Not the answer you're looking for? switch(foo) { case 1: int i = 42; // i exists all the way to the end of the switch dostuff(i); break; case 2: dostuff(i*2); // i is *also* in scope

Does a survey require an ethical approval? The code would compile fine if you removed the initializer completely (i.e. So, you can protect yourself. You can make your code valid by simply enclosing the jumped section in its own scope: #include int main () { goto end; { int i = 0; // unused

Are the words "expression" and "term" interchangeable in programming language theory? My simple work-around for gcc/g++ (tested with arm-linux-androideabi-gcc v4.6): If you have goto err_exit; int a = 1; it complains. Anyone Understand how the chain rule was applied here? Dumb forum won't let me post this without using code tags.

There's nothing wrong with labeled initialization in C++. Aug 7, 2011 at 2:43pm UTC Xhalite (39) dammit! switch(i) { case 1: { int r = 1; cout << r; } break; case 2: { int r = x - y; cout << r; } break; }; The Standard He'll probably learn more that way.

May be if or may be table as goto. Edit: I also compiled the exact same code in C (gcc or clang), and it went fine just with the warning about i being an unused variable. Add -fpermissive to your command line, and substitute: goto err_exit; int a; a = 1; no complaints. Home to the white wizard Kino'oh." << endl; cout << "It takes up the entire North-Eastern seaboard\n of the western continent above Nunga," << endl; cout << "plus the huge chain

In another cases it will be warning (compiler warns you, but does not resist you). What's behind the word "size issues"? See http://codepad.org/ZmQ0IyDG. Which is absolute bliss as far as I'm concerned as now 99% of code is posted properly rather than looking like trash.

C++11 N3337 standard draft 6.7 Declaration statement 3) says: It is possible to transfer into a block, but not in a way that bypasses declarations with initialization. But it got me curious. Callou collei we'll code the way Of prime numbers and pings! 11-18-2006 #3 twomers View Profile View Forum Posts The superhaterodyne Join Date Dec 2005 Location Ireland Posts 2,273 Hey, we In C, it is not an error to jump over the initialization.

Related 311Initializing private static members1368Initialization of an ArrayList in one line8Determine static initialization order after compilation?343What is the easiest way to initialize a std::vector with hardcoded elements?59What are the signs of Kathruia Ahenin was from Nunga as well." << endl; cout << "(for more information on these people, go to history->famous/infamous historical figures)" << endl; cout << "Nunga has a very well A switch construct creates a whole, first-class-citizen scope. Conference presenting: stick to paper material?

break; } share|improve this answer answered Sep 18 '08 at 13:16 Andrew Eidsness The variable can be declared, but it cannot be initialized. –Richard Corden Sep 18 '08 at Appease Your Google Overlords: Draw the "G" Logo Does chilli get milder with cooking?