fatal error cannot use string offset as an array cakephp Imlaystown New Jersey

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fatal error cannot use string offset as an array cakephp Imlaystown, New Jersey

How to decrypt a broken S/MIME message sent by Outlook? We're sticking to supporting the versions supported by WordPress itself. 1 year, 7 months ago Chris Risse Hey Greg, were you able to gain some insight into the issue? In Perl you could do this by specifying with {} but I don't think this is possible in PHP. Gregory _____________________________ Drupal Developer and Consultanthttp://adamagregory.comAcquia Certified Developer-Back end Specialist Log in or register to post comments ok...

With the passing of Thai King Bhumibol, are there any customs/etiquette as a traveler I should be aware of? Form.Inc#743666: Back button is not working on review page#351847: Cannot use string offset as an array..#346020: Fatal error when importing #358328: Error while accessing View Tool#684580: Recieve error after attempting to I do have a comma in place. drupal_get_form( $form_id = 'foo_form', class stdClass { public $nid = '42'; ... } ) ... 13.

The reason it isn't working is that you are passing it incorrect arguments Here is what it should look like function dipendenze_royalty($form_state, $your_arg1, $your_arg2, $your_arg3) { //enter your $form elements here. here is your answer: when using bracket syntax on strings, you are defining an offset, not a key. If you'll try to use: $give_me_foo = $obj->$var[0]; Instead of: $give_me_foo = $obj->foo[0]; You get "Cannot use string offset as an array [...]" error message as a result, because what you Skip to main content Skip to search Main Menu Drupal.org home Download & Extend Community Documentation Support Jobs Marketplace About Return to Content Search form Search Log in Create account Drupal

if($result['provider'] == 'Facebook') { 90. $provider = 'facebook'; 91. }else{ 92. $provider = 'twitter'; 93. } 94. $user = array( 95. 'provider' => $result['provider'], 96. 'id' => $result['uid'], 97. 'name' => What is the most expensive item I could buy with £50? In addition to appearing on the page, the error also appears in the metabox for the page builder. echo '

'; 105.

Log in or register to post comments Comment #4 jesss CreditAttribution: jesss commented December 28, 2012 at 5:45pm I updated the module -- the errors didn't appear until after the update. Can a Legendary monster ignore a diviner's Portent and choose to pass the save anyway? "Rollbacked" or "rolled back" the edit? Sum of neighbours How is the Heartbleed exploit even possible? Is it appropriate to tell my coworker my mom passed away?

Are there any rules or guidelines about designing a flag? change that and you should be ok. up vote 2 down vote favorite In my foreach, I see the following error: Fatal error: Cannot use string offset as an array [..] on line 97 88. asked 3 years ago viewed 11581 times active 1 year ago Visit Chat Related 500How to check if PHP array is associative or sequential?3Fatal error: Cannot use string offset as an

Try echo all those elements in the same way: $foo[0], $foo[1] & $foo[2]You will get individual character for each of those elements!661 Views · View UpvotesAnonymousWritten 160w agoOkay, found it.$arr = i guess i will dig into our custom theme to find out how to handle languageinterface calls. You also modify $form_state in the formbuilder. @ljrweb, see the FAPI documentation, or post a support request in the forum. EvenSt-ring C ode - g ol!f This riddle could be extremely useful House of Santa Claus What is the difference between i2pd and Kovri?

i edited the function, erasing arguments. Not the answer you're looking for? Try to var_dump $result['info']. foreach ($response as $result) { 89.

What is the difference between i2pd and Kovri? Hide this message.QuoraSign In Learning PHP PHP (programming language)Learning PHP: How can I produce the error "Fatal error: Cannot use string offset as an array in..."?I cannot produce the error, "Fatal How to decrypt a broken S/MIME message sent by Outlook? It seems that you do not need to run loop.

form_builder( $form_id = 'foo_form', $form = '\000', $form_state = array (...) 15. _form_builder_handle_input_element( $form_id = 'foo_form', $form = '\000', $form_state = array (...)) $form = '\0' (length=1) $form_id = 'foo_form' $form_state If not, I recommend closing. The same URL will work. 1 year, 8 months ago Chris Risse Ok, I have the development plugin enabled with the release disabled. Log in or register to post comments Comment #10 yannickoo CreditAttribution: yannickoo commented January 3, 2013 at 11:05am Status: Active ยป Fixed Great!

Fatal error: Cannot use string offset as an array in /home/servers/bf4c/bf4c.php on line 2447 line 2447 if (!isset($time_played[$player]["started"])) { $time_played[$player]["started"] = $time; } $time_played was overwritten elsewhere and defined as a Join them; it only takes a minute: Sign up Fatal error: Cannot use string offset as an array? I thought that you have a Linked Field but you didn't had a Linked Field that was not your problem. t.

How do I adjust this?...PHP: How can I access an associative array with a string using the shortest possible code?What are the most commonly used string and array functions in php?PHP Is there a place in academia for someone who compulsively solves every problem on their own? echo "

".$user['name']."

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php arrays loops foreach share|improve this question edited Jan 17 '14 at 10:53 asked Jan 17 '14 at 8:35 Chris Burton 40911037 what is the output of var_dump($response); or Browse other questions tagged php arrays loops foreach or ask your own question. Because PHP is a very forgiving programming language, I'd guess. It looks like what's happening is that for the field I'm using as the token in my linked field, the view mode is set to _custom.

Now I am trying to make it consistent and convert educations=>education=>school-name to educations=>education=>0=>school-name But getting error in code that i believe should work if(empty($educations['education'][0]['school-name'])) { $temp = array(); $temp['education'][0]=$educations['education']; $educations = share|improve this answer answered Jan 17 '14 at 9:58 AgileTillIDie 3891317 cloud.chrisburton.me/TQZC –Chris Burton Jan 17 '14 at 10:04 add a comment| up vote 0 down vote You declare So I think the snippet at line 207 is too broad. when i comment out the affected lines: //$options['attributes']['class'] = $classes; //$output .= '