gcc error is an inaccessible base of Ventura Iowa

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gcc error is an inaccessible base of Ventura, Iowa

How to handle a senior developer diva who seems unaware that his skills are obsolete? Remember that you should destroy objects that you create. asked 4 years ago viewed 5493 times active 4 years ago Linked 547 Difference between private, public, and protected inheritance Related 75C++ inheritance - inaccessible base?3C++ Problem: Class Promotion using derived Consider the 2nd bullet- 'R occurs in a member or friend of a class N,...'.

Is it plausible for my creature to have similar IQ as humans? How? If, for example, the class provided a member function A* get_base_pointer() { return this; }; there would be nothing wrong with using the resulting pointer. –Pete Becker Sep 5 at 14:23 It just means that private members of the base class will not be visible from the derived class. - Guillaume.

share|improve this answer edited Sep 5 at 14:46 answered Sep 5 at 14:30 user2079303 31.1k22352 any gotchas with this method? –Abhinav Gauniyal Sep 5 at 15:12 Also share|improve this answer answered Aug 12 '12 at 1:28 WendiKidd 2,91522442 I thought that making it protected gave it more access. The reason the main() function doesn't know it is that you made class derived inherit PRIVATELY from class base. PS.

In Harry Potter book 7, why didn't the Order flee Britain after Harry turned seventeen? You are apparently assuming that access qualifiers like public BB, B work in the same way as variable declarations, e.g., int x, y i.e., that they continue in effect for identifiers That means you can't cast the derived class to the base class: the relationship isn't known to the caller. Why can't we use the toilet when the train isn't moving?

Private inheritance does not assert that though. Normally one has to tell the compiler how to print the object. share|improve this answer edited Sep 9 '10 at 9:15 RBerteig 29k356102 answered Sep 9 '10 at 8:27 Windows programmer 6,3181418 @WP: Can you please elaborate on your answer –Bruce share|improve this answer answered Aug 12 '12 at 1:27 Daniel A.

Is there any way to know when NOT to use my Oyster card? How to draw a path with coordinates defined by f(x) How should I deal with a difficult group and a DM that doesn't help? Compute the kangaroo sequence What is the first movie to show this hard work message at the very end? You are using private inheritance hence the conversion from derived* to base* is failing.

asked 4 years ago viewed 35954 times active 4 years ago Linked 0 can I make a pointer of base class to point to a derived object if inheritance type is It just means that private members of the base class will not be visible from the derived class. - Guillaume. I don't seem to be able to make that call in my main function c++ inheritance share|improve this question edited Nov 27 '11 at 8:30 aaaidan 3,39933875 asked Jan 31 '11 In the United States is racial, ethnic, or national preference an acceptable hiring practice for departments or companies in some situations?

Public inheritance is no more than a way to make the compiler stop complaining. V -- Please remove capital 'A's when replying by e-mail I do not respond to top-posted replies, please don't ask May 22 '07 #2 P: n/a Howard "Stefan Weber"

share|improve this answer answered Mar 12 '12 at 5:00 tmpearce 9,62212036 Thanks, but it somehow doesn't make sense. How to handle a senior developer diva who seems unaware that his skills are obsolete? share|improve this answer answered Sep 5 at 14:56 skypjack 15.5k82371 any gotchas with this method? –Abhinav Gauniyal Sep 5 at 15:12 @AbhinavGauniyal I find it easier to share|improve this answer answered Sep 9 '10 at 8:25 Douglas Leeder 37.1k563109 Why cant I do this?

Was missing a public statement on my derived class definition –User Jul 11 '12 at 22:17 add a comment| up vote 7 down vote Chusbad provided an in-depth explanation involving the How can I make LaTeX break the word at the end of line more beautiful? Acutally, I know that this error message occurs when doing something like "class Bar : private Foo" (i.e. Browse other questions tagged c++ or ask your own question.

But what I'm trying to do is to get the first call. The only thing I see unusual is the use of void as a parameter type. What (combination of) licenses is popular for public/shared proprietary software (“Feel free to contribute, but only we can make commercial use”)? Physically locating the server With the passing of Thai King Bhumibol, are there any customs/etiquette as a traveler I should be aware of?

I get the error: source.cpp: In function 'int main()': source.cpp:12:31: error: 'A' is an inaccessible base of 'B' class A {}; class B : A {}; void f(const A &) { I will update my post accordingly –Chubsdad Sep 9 '10 at 8:54 See Douglas Leeder's and ereOn's answers for human readable and quick solutions. –mwjohnson Jan 7 '14 at How to handle a senior developer diva who seems unaware that his skills are obsolete? It just means that private members of the base class will not be visible from the derived class. - Guillaume.

If we wanted to provide essentially the same with inheritance, we would probably use private inheritance, so std::stack would be something like: class stack : private vector { // ... }; Does anybody see the problem? Get a better compiler. I've marked below where I am getting my error at: (***) Thank you to anyone who takes time to look over this main: 1
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#include "UListType.h" #include "UListType.h" #include "OListType.h" #include

This answer has a great explanation of private/protected/public: stackoverflow.com/a/860353/1023783 Let me know if you're still confused after reading it and I'll try to elaborate! –WendiKidd Aug 12 '12 at 2:02 Anyway, hopefully that makes sense. Browse other questions tagged c++ class inheritance polymorphism or ask your own question. It prevents objects from being considered extensions of the base class.

It seems like my understanding is lacking here. But you assignment A *ptr = new B("c++"); breaks this hiding, because you use an A*. Hence the error. How does NumPy solve least squares for underdetermined systems?

Compute the kangaroo sequence With modern technology, is it possible to permanently stay in sunlight, without going into space? The base is inaccessible (as the compiler told you already) so the cast fails to compile. inherit the code but withouth polymorphism). Does anybody see the problem?

Not the answer you're looking for? It fails to compile otherwise. I have the following in my main: int some_ftn(Foo *f) { /* some code */ }; Bar b; some_ftn(&b); And the class Bar inheriting from Foo in such a way: class In a struct , inheritance is public by default. –Travis Gockel Jan 31 '11 at 2:26 add a comment| Your Answer draft saved draft discarded Sign up or log in

Unsubstantiated Why do train companies require two hours to deliver your ticket to the machine? Can Communism become a stable economic strategy? Could you elaborate more? –Slims Aug 12 '12 at 1:32 1 @Slims Nope, not quite! This clause does not apply as 'R'(main) is neither a member nor friend of 'N'(Derived) Consider the 3rd bullet- 'R occurs in a member or friend of a class P....'.