fatal error cannot use string offset as an array php5 Kennesaw Georgia

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fatal error cannot use string offset as an array php5 Kennesaw, Georgia

Here's the output: array ( 'SearchResult' => array ( 'Id' => array ( 0 => '077BE86E-372F-4390-8F0A-EC163706D8FC', 1 => '318A39E4-EC95-4DA9-B92E-4C081E10A974', There is something going weird in your code, not sure what it is but yea. Regards, Joseph Log in or register to post comments Comment #12 nicholas.alipaz CreditAttribution: nicholas.alipaz commented January 12, 2011 at 11:08pm FileSize Screenshot-7.png180.04 KB Screenshot-6.png172.14 KB I did a quick meld diff EvenSt-ring C ode - g ol!f Near Earth vs Newtonian gravitational potential Truth in numbers Is the NHS wrong about passwords?

I don't know how to roll patches and fix this stuff by myself yet, but I hope that helps regardless :) Log in or register to post comments Comment #6 nicholas.alipaz Let me know if this helped you or if I am not clear on anything. How do I explain that this is a terrible idea? Thank you for the debug information.

What you can do in this case is to use curly braces, which will assure that at first is called content of $var, and subsequently the rest of message-sent: $give_me_foo = In a __get() method I was using the given argument as a property, as in (simplified example): function __get($prop) { return $this->$prop; } ...i.e. $obj->fred would access the private/protected fred property Thanks. Log in or register to post comments Comment #10 yannickoo CreditAttribution: yannickoo commented January 3, 2013 at 11:05am Status: Active » Fixed Great!

elseif ($context['view_mode'] == '_custom' && is_array($context['display'])) { $display = $context['display']; } Thoughts? asked 6 years ago viewed 48820 times active 1 year ago Linked 3 “Cannot use string offset as an array” error -1 PHP File Upload does not work 0 Fatal error: please explain so I can try to see if this helps my issue Thanks! -=b=- Log in or register to post comments Comment #8 nicholas.alipaz CreditAttribution: nicholas.alipaz commented November 22, 2010 Ken Back to top #7 RIRedinPA RIRedinPA Advanced Member Members 256 posts Posted 01 April 2009 - 10:03 PM Hi Ken Thanks for the help.

I hit the back button to the last page and (sometimes) see "warning: extract() [function.extract]: First argument should be an array in [site-name]/modules/autoassignroleblocks/autoassignroleblocks.module on line 206." Please let me knoe if I have the "pages with no navigation" and a path such as "sign_up_rolename." I've enabled the roles in the Auto Assign Role Block menu and move the Blocks into the content What is the difference between i2pd and Kovri? So when I var_dump my $_POST["formData"] I get an array that looks like this: array(42) { [0] => array(2) { ["name"] => string(2) "id"; ["value"] => string(4) "3972"; } [1] =>

Merci ++ Répondre avec citation 0 0 14/02/2008,11h01 #2 batataw Membre éprouvé Inscrit enseptembre 2007Messages956Détails du profilInformations personnelles :Localisation : FranceInformations forums :Inscription : septembre 2007Messages : 956Points : 1 The default value for mode is 0. This forum is now closed to new posts, but you can browse existing content. Log in or register to post comments Comment #4 jesss CreditAttribution: jesss commented December 28, 2012 at 5:45pm I updated the module -- the errors didn't appear until after the update.

Running dpm($settings), there are two different versions of the array. Solution $b = $a['text1']; echo $b['text2']; // prints: sometext .. I couldn't reproduced it with creating a new Panel page and add an exisiting node to it. How do I help minimize interruptions during group meetings as a student?

Example that generates error: $foo='bar'; $foo[0]='bar'; Get error message Fatal error: Cannot use string offset as an array in … Explanation $foo was declared as a string in $foo='bar'. $foo[0] is Can Dandelion defeat you? You can find out more information about the move and how to open a new account (if necessary) here. Does chilli get milder with cooking?

This exact copy I've attached is working perfectly on my server right now, whereas the module on d.o. Log in or register to post comments Comment #2 davethedruper CreditAttribution: davethedruper commented September 26, 2010 at 4:38pm Thank you for the response, I've reproduced it again on a third site If anyone has a better solution to what it was I did in the module, then I would be glad to accept suggestions/patches. I will probably do some more testing on my machine and let you know what I find out if anything.

my code before(given same error): $arr2= ""; // this is the problem and solve by replace this $arr2 = array(); for($i=2;$i

Répondre avec citation 0 0 14/02/2008,11h02 #3 Gats Membre confirmé Développeur WebInscrit enavril 2005Messages397Détails du profilInformations personnelles :Âge : 32Informations professionnelles :Activité : Développeur WebInformations forums :Inscription : avril 2005Messages I can't even reproduce the array, but if I copy and paste your array, the key is an asterisk. I've attached essentially the one i have and edited the version info and updated the name to reflect the new name. Are there any rules or guidelines about designing a flag?

What's causing this? Log in or register to post comments Comment #3 yannickoo CreditAttribution: yannickoo commented December 28, 2012 at 5:37pm I will try that again. asked 3 years ago viewed 308 times active 3 years ago Linked 10 PHP 5.4's simplified string offset reading Related 1267Length of a JavaScript object (or associative array)1328Delete an element from Running cron didn't have an affect on it but I seem to have focused it on moving the AutoAssign Role Blocks to the content section.

Several functions may not work. Please test again on a default drupal installation with only this module and it's requirements. share|improve this answer answered Sep 28 '13 at 2:20 IMSoP 29.4k43455 Actually just figured it out (I need to get myself a rubber duck). I'm not entirely sure, but $data could be being implicitly initialised to an empty string, which you are then trying to dereference and assign to.

Back to top #3 RIRedinPA RIRedinPA Advanced Member Members 256 posts Posted 31 March 2009 - 01:16 PM I think it's just saying that you are trying to count something that if (!isset($settings['linked_field']) || !count($settings['linked_field']) || !isset($settings['linked_field']['linked'])) { I don't have access to git, but maybe somebody else could make a patch?