excel vb error 2015 Cornelia Georgia

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excel vb error 2015 Cornelia, Georgia

If your suggestion is correct Steve I would expect it to happen all the time.I am wondering if this is somehow enviromental. Any idea? Dim ws as Worksheet Set ws = Sheets(1) IsError(Application.Match(ws.Range("IdSelect").Value, ws.Range("ProjectList"), 0)) Then And here is for you to read on for error handling on on match. It did not made any difference.

You may have to register before you can post: click the register link above to proceed. Browse other questions tagged arrays excel vba value array-formulas or ask your own question. Code: Sub test() ''this code is in file B Dim accR As Long Dim res As Variant 'Set Account to check details ''be sure sheet is active Sheets("Group").Activate accCol = "A" You need to use square brackets in the question editor. –bonCodigo Jan 7 '13 at 0:03 Ok thanks, that explains it! :-) Thanks for editing! –Matthias Jan 7 '13

When I play arround with the affected cell where it gets the data from then it is happening when the cell has quite an amount of characters (~3000 chars). In some cases I get in the array a #VALUE (error 2015) and I have no clue why. Forum New Posts FAQ Calendar Forum Actions Mark Forums Read Quick Links Today's Posts View Site Leaders What's New? All contents Copyright 1998-2016 by MrExcel Consulting.

I am using Excel 2003.I have one specific DBRW that In the cell works every time - returning a decimal number. Powered by vBulletin® Version 4.1.8 Copyright © 2012 vBulletin Solutions, Inc. For that I am checking whether the project number is not part of the list of projects. Top lotsaram MVP Posts: 2841 Joined: Fri Mar 13, 2009 11:14 am OLAP Product: TM1, CX Version: 10.1 10.2 Excel Version: 2010 2013 365 Location: Switzerland Re: VBA 'Evaluate' function generates

I have seen a MS article where Evaluate functions that include dates can be an issue but it does not appear to apply in this situation and it is for an Which option did Harry Potter pick for the knight bus? Share Share this post on Digg Del.icio.us Technorati Twitter Office 2010/2016 Reply With Quote « Previous Thread | Next Thread » Like this thread? That is what I need and did not want to loop through the cell using InStr.

Any suggestion is welcome Thanks again VB: Sub compte2() 'Dim date_format As Date Dim rngC As Range, rngJbn, rngJbm Dim rngD As Range Dim newValueArray() Dim rCell As Range On Error If you don't like Google AdSense in the posts, register or log in above. If Dumbledore is the most powerful wizard (allegedly), why would he work at a glorified boarding school? As long as the length of the string is less than or equal to 255 characters, the return value is the desired string.

By langel in forum Excel General Replies: 5 Last Post: December 12th, 2004, 17:50 VBA: matrix inversion error 2015 By mgr in forum Excel General Replies: 1 Last Post: September 2nd, Case Else ' some code End Select theEnd: ' jiuk some code End Sub Sub err2015() MsgBox Err.Number End Sub Excel Video Tutorials / Excel Dashboards Reports Reply With Quote July Forum Today's Posts FAQ Calendar Community Groups Forum Actions Mark Forums Read Quick Links What's New? The "ubound -1" of the returned array will be your count.

I am using Excel 2002. Share a link to this question via email, Google+, Twitter, or Facebook. Physically locating the server Can a Legendary monster ignore a diviner's Portent and choose to pass the save anyway? So that values in the array with more than 255 chars get passed with #VALUE!

That is Cool! What is a type system? To start viewing messages, select the forum that you want to visit from the selection below. Here is the FAQ for this forum. + Reply to Thread Results 1 to 2 of 2 error 2015 performing vlookup Thread Tools Show Printable Version Subscribe to this Thread… Mark

IsError(arr(i,1)) -- see comment in source code -- does not really help because I need the data from the cell for further processing –megloff Feb 16 at 17:05 3 Might ERROR The requested URL could not be retrieved The following error was encountered while trying to retrieve the URL: http://0.0.0.8/ Connection to 0.0.0.8 failed. Oddly enoughbthat you do it correct on the next line at Debug.Print Application.Match(Range("IdSelect").Value, Worksheets("Input").Range("ProjectList"), 0) So try this please: (it take me 100 years to format my own post on mobile.....). Does chilli get milder with cooking?

All rights reserved. Join them; it only takes a minute: Sign up Excel VBA - Array Formula returns #VALUE! (Error 2015) in case a cell contains more than 255 characters up vote 2 down The value of the searchformula is: "SEARCH(".",$A$1,1)". Is "halfly" a word?

Perhaps the argument Byref Arr() As Variant should be without (). 2. Browse other questions tagged excel vba excel-vba find or ask your own question. so I assume there is a limitation in passing arrays from native formulas to own functions? This way the code won't run into an error when Application.Evaluate returns Error 2042.