How close will the result be to the true answer? Once again we will start off with a convergent series Â which in this case happens to be an alternating series that satisfies the conditions of the alternating series test, so we My Students - This is for students who are actually taking a class from me at Lamar University. Become a "now-ist" - Duration: 12:32.

[email protected] 418 views 16:02 Divergence test - Duration: 7:56. SeriesEstimating infinite seriesEstimating infinite series using integrals, part 1Estimating infinite series using integrals, part 2Alternating series error estimationAlternating series remainderPractice: Alternating series remainderCurrent time:0:00Total duration:9:180 energy pointsAP Calculus BC|Series|Estimating infinite seriesAlternating Show Answer Answer/solutions to the assignment problems do not exist. Loading...

Loading... This is going to be, let's see ... So, if we could figure out some bounds on this remainder, we will figure out the bounds on our actual sum. What are we to think of this number?

In general, the further away is from , the bigger the error will be. The links for the page you are on will be highlighted so you can easily find them. The system returned: (22) Invalid argument The remote host or network may be down. Sign in to add this video to a playlist.

Khan Academy 237,696 views 11:27 Calculus 2 Lecture 9.7: Power Series, Calculus of Power Series, Ratio Test for Int. Included in the links will be links for the full Chapter and E-Book of the page you are on (if applicable) as well as links for the Notes, Practice Problems, Solutions Sign in to add this to Watch Later Add to Loading playlists... Letâ€™s take a look at an example.

It is especially true for some exponents and occasionally a "double prime" 2nd derivative notation will look like a "single prime". Plus some remainder. This, you go minus one over two squares, is minus 1/4 plus 1/9 minus 1/16 plus 1/25 ... Please be as specific as possible in your report.

Generated Sat, 15 Oct 2016 06:55:29 GMT by s_wx1131 (squid/3.5.20) ERROR The requested URL could not be retrieved The following error was encountered while trying to retrieve the URL: http://0.0.0.10/ Connection I would love to be able to help everyone but the reality is that I just don't have the time. R four is going to be greater than zero. Khan Academy 164,109 views 7:56 Radius of convergence using Ratio Test - Duration: 7:18.

This, this term right over here is positive. All of this other stuff, I don't want even the brackets to end. Khan Academy 66,824 views 8:46 Estimating error/remainder of a series - Duration: 12:03. Please do not email asking for the solutions/answers as you won't get them from me.

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R sub four is going to be less than 1/25. How do I download pdf versions of the pages? Mr. Now, this was one example.

Common denominator here, see, nine times 16 is 144. Note If you actually compute the partial sums using a calculator, you will find that 7 terms actually suffice. There are some tricks, but none of them really reliable. Example 1 Â Using Â to estimate the value of .

Let's write the remainder down. Some of the equations are too small for me to see! Another option for many of the "small" equation issues (mobile or otherwise) is to download the pdf versions of the pages. Rating is available when the video has been rented.

Long Answer with Explanation : I'm not trying to be a jerk with the previous two answers but the answer really is "No". Sign in 7 Loading... Now, since Â we also know that When using the comparison test it is often the case that the bn are fairly nice terms and that we might actually Absolute convergence Back to Theory - Introduction to Series ERROR The requested URL could not be retrieved The following error was encountered while trying to retrieve the URL: http://0.0.0.8/ Connection to

Sign in to add this video to a playlist. Note that here we asked how large the error RN is when we sum up to N, but often the question goes the other way around. I really got tired of dealing with those kinds of people and that was one of the reasons (along with simply getting busier here at Lamar) that made me decide to In this case weâ€™ve used the ratio test to show that Â is convergent.Â To do this we computed and found that .

Links to the download page can be found in the Download Menu, the Misc Links Menu and at the bottom of each page. Let me know what page you are on and just what you feel the typo/mistake is.