In that case, a problem like 10 / 0 would have some value, which we'll call x. Which, good news, means you can relax—we haven't shattered all that you know and love about math. now factor each side, (a+b)(a-b) = b(a-b), and divide each side by (a-b), to get a + b = b. finally let a and b be equal to 1, which shows that 2 =1.

Follow 4 answers 4 Report Abuse Are you sure you want to delete this answer? Mathematics and plausibe reasoning. 1. HinzufÃ¼gen MÃ¶chtest du dieses Video spÃ¤ter noch einmal ansehen? NÃ¤chstes Video A Proof that 0 = 1 (Can You Spot the Mistake?) - Dauer: 3:33 patrickJMT 225.048 Aufrufe 3:33 40 "Proofs" of a Flat Earth: A Rapid Fire Response -

Answer Questions I have a problem. 775-problem communicating with dish. Wird geladen... Well-known fallacies also exist in elementary Euclidean geometry and calculus. ISBN978-1-4008-3029-9.

The error in each of these examples fundamentally lies in the fact that any equation of the form x 2 = a 2 {\displaystyle x^{2}=a^{2}} has two solutions, provided a â‰ Explain the error in the following false proof.? Then, by taking a square root, cos x = 1 − sin 2 x {\displaystyle \cos x={\sqrt {1-\sin ^{2}x}}} so that 1 + cos x = 1 + Therefore, when you say to divide both sides by a - b is wrong because you can't divide by zero.

WÃ¤hle deine Sprache aus. Quick & Dirty Tips™ and related trademarks appearing on this website are the property of Mignon Fogarty, Inc. Maxwell, E. Multivalued functions[edit] Many functions do not have a unique inverse.

The problem is that antiderivatives are only defined up to a constant and shifting them by 1 or indeed any number is allowed. And I say subtle because this proof is structured in such a way that you might never even notice that division by zero is happening. Power and root[edit] Fallacies involving disregarding the rules of elementary arithmetic through an incorrect manipulation of the radical. As an another example of the danger of squaring both sides of an equation, consider the fundamental identity[8] cos 2 x = 1 − sin 2 x {\displaystyle \cos

Failing to do so results in a proof of[7] 5 = 4. {\displaystyle 5=4.} Proof: Start from − 20 = − 20 {\displaystyle -20=-20} Write this as 25 − 45 But nuts or not, these are exactly the things we'll be talking about today.Of course, there will be a trick involved because 1 + 1 is certainly equal to 2…thank goodness! Part 1 of 3. - Dauer: 10:01 AAM AAP 15.503 Aufrufe 10:01 Weitere VorschlÃ¤ge werden geladenâ€¦ Mehr anzeigen Wird geladen... Learn more You're viewing YouTube in German.

subtract b^2 from both sides to get a^2 - b^2 = ab - b^2. Then I'll show you why this "proof" is indeed, as you suspected, ridiculous. If I move b to the right side I'll get a = b - b, so a = 0. Use the insert code snippet button (4th from last) for syntax highlighting Your name to display (optional): Email me at this address if my answer is selected or commented on:Email me

This one's a classic, but people usually don't bother with the explanation, letting morons argue about it in the comments. i.e. Heath, Sir Thomas Little; Heiberg, Johan Ludvig (1908), The thirteen books of Euclid's Elements, Volume 1, The University Press. And remember to become a fan of the Math Dude onFacebookwhere you’ll find lots of great math posted throughout the week.

Geometry[edit] Many mathematical fallacies in geometry arise from using in an additive equality involving oriented quantities (such adding vectors along a given line or adding oriented angles in the plane) a Wird geladen... Hochgeladen am 24.03.2011If you don't like math, don't bother. Such an argument, however true the conclusion, is mathematically invalid and is commonly known as a howler.

Melde dich an, um dieses Video zur Playlist "SpÃ¤ter ansehen" hinzuzufÃ¼gen. Draw line OR perpendicular to AB, line OQ perpendicular to AC Draw lines OB and OC By AAS, â–³RAO â‰… â–³QAO (âˆ ORA = âˆ OQA = 90; âˆ RAO = âˆ QAO; AO = now factor each side, (a+b)(a-b) = b(a-b), and divide each side by (a-b), to get a + b = b. If we remove a horse from the group, we have a group of N - 1 horses of the same colour.

This quantity is then incorporated into the equation with the wrong orientation, so as to produce an absurd conclusion. For example, the reason validity fails may be a division by zero that is hidden by algebraic notation. Courier Corporation. This "proof" shows that all horses are the same colour.[14] Let us say that any group of N horses is all of the same colour.

If we were additionally given the fact that any two horses shared the same color, we could correctly induct from the base case of N = 2. In particular, when x is set to Ï€, the second equation is rendered invalid. The following example uses division by zero to "prove" that 2 = 1 {\displaystyle 2=1} , but can be modified to prove that any number equals any other number. Login Register GeeksforGeeks Q&A GeeksforGeeks All Activity Q&A Questions Hot!

The error in the proof is the assumption in the diagram that the point O is inside the triangle. Melde dich bei YouTube an, damit dein Feedback gezÃ¤hlt wird. Which means the operation of dividing by zero is what's dubbed "undefined."The second way to think about the screwiness of dividing by zero—and the reason we can't do it—is to imagine Consider the equation a = b.

the square root of the square of âˆ’2 is 2. all horses are the same colour. Navigation Panel: Go up to Classic Fallacies index Go down to first subsection This is Not the Fallacy Go forward to 1=2: A Proof using Complex Numbers Switch to text-only version Proof by induction[edit] There exist several fallacious proofs by induction in which one of the components, basis case or inductive step, is incorrect.

Let's imagine for a second that division by zero is fine and dandy. You can only upload a photo or a video. Subtract b ^ 2 from both sides to get a ^ 2 - b ^ 2 = ab - b ^ 2. For instance, a naive use of integration by parts can be used to give a false proof that 0 = 1.[6] Letting u = 1 log x {\displaystyle \textstyle u={\frac

Wird geladen... When you think you've figured it out, click on that step and the computer will tell you whether you are correct or not, and will give an additional explanation of why So 10 / 0 =x. Probably.

Wird verarbeitet... The implication "Every N horses are of the same color, then N+1 horses are of the same color" works for any N greater than one, but fails to be true when